r^2=324

Solution for r^2=324 equation:

r^2=324

We move all terms to the left:

r^2-(324)=0

a = 1; b = 0; c = -324;
Δ = b2-4ac
Δ = 02-4·1·(-324)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*1}=\frac{-36}{2}
=-18
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*1}=\frac{36}{2}
=18
$